48÷2(9+3) = ???

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The Prodigalson;2366358 said:
Isn't 2(9+3) a complete term? When did they start breaking those up?

This right here. People keep saying pemdas but then say multiplication and division are equal in priority but don't realze that multiplication is a parenthetical operation therefore supersedes anything else.
 
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MorganFreemanKing;2366432 said:
This right here. People keep saying pemdas but then say multiplication and division are equal in priority but don't realze that multiplication is a parenthetical operation therefore supersedes anything else.

yes, it is and this is where they go wrong.
 
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Niggas still trying to get this answer? lol I spoke with someone on this. They said 2. Then they explained why its 288 when I said that people were saying 2 was wrong. He almost changed my mind. Fuck all that. The answer is 2.
 
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Super Lex;2366901 said:
Niggas still trying to get this answer? lol I spoke with someone on this. They said 2. Then they explained why its 288 when I said that people were saying 2 was wrong. He almost changed my mind. Fuck all that. The answer is 2.

LOL, when sure niggaz ain't sure.
 
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yawn.jpg


.............
 
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konceptjones;2366413 said:
The way you do this problem per the rules you SHOULD have learned in high school algebra is as follows:

Always process the equations inside parenthesis FIRST.

48/2(9+3) = 48/2(12)
Next, process multiplication in order from left to right:

48/2(12) = 48/2*12 = 48/24

Finally, process the division

48/24 = 2

This is the answer.

Multiplication does not take precedence over division. I have found at least one web site that holds the 2(9+3) must be resolved to a single component. They call it multiplication by juxtaposition. That is 2(9+3) implies (2(9+3)). Given this interpretation the answer would be 2. This seems patently sloppy though since 2(9+3) should be interchangeable with 2*(9+3) and would not be with this interpretation.

Your position that multiplication precedes division violates the associative and communicative laws. The associative law states

a*b*c
(a*b)*c
a*(b*c)

all are identical. The communicative states

a*b*c = c*b*a

A multiplicative reciprocal is 1/x or x^-1 which when multiplied by x results in one. With this all of the following must produce the same result

6*4*3
6*3*4

Also

6*4*(1/3) ... Here I wanted to write one third but can not given the text used.
6*(1/3)*4

Given I am using the multiplicative reciprocal of 3 I can replace one third with division by 3

6*4/3 = 6/3*4

Multiplication and division must be resolved from left to right without precedent unless parentheses exist.
 
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whar67;2367033 said:
Multiplication does not take precedence over division. I have found at least one web site that holds the 2(9+3) must be resolved to a single component. They call it multiplication by juxtaposition. That is 2(9+3) implies (2(9+3)). Given this interpretation the answer would be 2. This seems patently sloppy though since 2(9+3) should be interchangeable with 2*(9+3) and would not be with this interpretation.

Your position that multiplication precedes division violates the associative and communicative laws. The associative law states

a*b*c

(a*b)*c

a*(b*c)

all are identical. The communicative states

a*b*c = c*b*a

A multiplicative reciprocal is 1/x or x^-1 which when multiplied by x results in one. With this all of the following must produce the same result

6*4*3

6*3*4

Also

6*4*(1/3) ... Here I wanted to write one third but can not given the text used.

6*(1/3)*4

Given I am using the multiplicative reciprocal of 3 I can replace one third with division by 3

6*4/3 = 6/3*4

Multiplication and division must be resolved from left to right without precedent unless parentheses exist.

whoa.jpg


but seriously, you do realize that your analysis of the equation fits squarely within my explanation, right?
 
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konceptjones;2367125 said:
but seriously, you do realize that your analysis of the equation fits squarely within my explanation, right?

Since you believe multiplication takes precedence over division the statements

6*4/3 != 6/3*4

They in fact do. If multiplication takes precedence then

6/3*4 = 6/12 = 1/2

While

6*4/3 = 24/3 = 8

The first should proceed like so

6/3*4 = 2 * 4 = 8
 
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whar67;2367167 said:
Since you believe multiplication takes precedence over division the statements

6*4/3 != 6/3*4

They in fact do. If multiplication takes precedence then

6/3*4 = 6/12 = 1/2

While

6*4/3 = 24/3 = 8

The first should proceed like so

6/3*4 = 2 * 4 = 8

Niggaz put in factorials now? Whoa.
 
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The Prodigalson;2367310 said:
Niggaz put in factorials now? Whoa.

A factorial would represent the product of a sequence of integers. Written 3! it would represent 3x2x1 or 6. I am just doing basic multiplication and division. I have to use the '/' symbol since I have no other keystroke for division.
 
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